Python Concordance program - alphabetical order

Question

I'm trying to write a program that displays a concordance for a file. It should output the unique words and their frequencies in alphabetical order. This is what I have, but it's not working. Tips?

FYI - I know NOTHING about computer programming!! I'm taking this class to satisfy a high school math endorsement requirement.

f = open(raw_input("Enter a filename: "), "r")
myDict = {}
linenum = 0

for line in f:
  line = line.strip()
  line = line.lower()
  line = line.split()
  linenum += 1

for word in line:
    word = word.strip()
    word = word.lower()

    if not word in myDict:
        myDict[word] = []

    myDict[word].append(linenum)


print "%-15s %-15s" %("Word", "Line Number")
for key in sorted(myDict):
    print '%-15s: %-15d' % (key, myDict(key))

Answer 1

You need to use myDict[key] for getting from a dictionary. And since that's a list, you need to use sum(myDict[key]) for frequency (count)

f = "HELLO HELLO HELLO WHAT ARE YOU DOING"
myDict = {}
linenum = 0

for word in f.split():
    if not word in myDict:
        myDict[word] = []

    myDict[word].append(linenum)


print "%-15s %-15s" %("Word", "Frequency")
for key in sorted(myDict):
    print '%-15s: %-15d' % (key, len(myDict[key]))

Results in:

Word            Frequency
ARE            : 1
DOING          : 1
HELLO          : 3
WHAT           : 1
YOU            : 1