Tell urllib2 to use custom DNS

Attila O. picture Attila O. · Feb 10, 2010 · Viewed 12.6k times · Source

I'd like to tell urllib2.urlopen (or a custom opener) to use 127.0.0.1 (or ::1) to resolve addresses. I wouldn't change my /etc/resolv.conf, however.

One possible solution is to use a tool like dnspython to query addresses and httplib to build a custom url opener. I'd prefer telling urlopen to use a custom nameserver though. Any suggestions?

Answer

MattH picture MattH · Feb 10, 2010

Looks like name resolution is ultimately handled by socket.create_connection.

-> urllib2.urlopen
-> httplib.HTTPConnection
-> socket.create_connection

Though once the "Host:" header has been set, you can resolve the host and pass on the IP address through down to the opener.

I'd suggest that you subclass httplib.HTTPConnection, and wrap the connect method to modify self.host before passing it to socket.create_connection.

Then subclass HTTPHandler (and HTTPSHandler) to replace the http_open method with one that passes your HTTPConnection instead of httplib's own to do_open.

Like this:

import urllib2
import httplib
import socket

def MyResolver(host):
  if host == 'news.bbc.co.uk':
    return '66.102.9.104' # Google IP
  else:
    return host

class MyHTTPConnection(httplib.HTTPConnection):
  def connect(self):
    self.sock = socket.create_connection((MyResolver(self.host),self.port),self.timeout)
class MyHTTPSConnection(httplib.HTTPSConnection):
  def connect(self):
    sock = socket.create_connection((MyResolver(self.host), self.port), self.timeout)
    self.sock = ssl.wrap_socket(sock, self.key_file, self.cert_file)

class MyHTTPHandler(urllib2.HTTPHandler):
  def http_open(self,req):
    return self.do_open(MyHTTPConnection,req)

class MyHTTPSHandler(urllib2.HTTPSHandler):
  def https_open(self,req):
    return self.do_open(MyHTTPSConnection,req)

opener = urllib2.build_opener(MyHTTPHandler,MyHTTPSHandler)
urllib2.install_opener(opener)

f = urllib2.urlopen('http://news.bbc.co.uk')
data = f.read()
from lxml import etree
doc = etree.HTML(data)

>>> print doc.xpath('//title/text()')
['Google']

Obviously there are certificate issues if you use the HTTPS, and you'll need to fill out MyResolver...