When I run the following code in Python 3.3:
import urllib
tempfile = urllib.request.urlopen("http://yahoo.com")
I get the following error:
I did this too to verify:
What am I doing wrong?
The urllib
module has been split into parts and renamed in Python 3 to urllib.request
, urllib.parse
, and urllib.error
.
Import urllib.request
instead of urllib
.
import urllib.request