Python: Retrieving only POP3 message text, no headers

Question

I'm trying to make a Python program that retrieves only the body text of an email without passing headers or any other parameters. I'm not sure how to go about this.

The goal is to be able to send basic commands to a program via message text.

What I have now is this:

import poplib

host = "pop.gmail.com"
mail = poplib.POP3_SSL(host)
print mail.getwelcome()
print mail.user("user")
print mail.pass_("pass")
print mail.stat()
print mail.list()
print ""

if mail.stat()[1] > 0:
    print "You have new mail."
else:
    print "No new mail."

print ""

numMessages = len(mail.list()[1])
for i in range(numMessages):
    for j in mail.retr(i+1)[1]:
        print j

mail.quit()
input("Press any key to continue.")

Which is all fine, except when "print J" is executed it prints the entire message, including headers. I just want to extract the body text without any additional garbage.

Can anyone help? Thanks!

Answer 1

I would use email module to get the body of email message with get_payload() method which skips header info.

I added few lines to your code (they are marked with # new statement at the end of line)

import poplib
import email # new statement

host = "pop.gmail.com"
mail = poplib.POP3_SSL(host)
print mail.getwelcome()
print mail.user("user")
print mail.pass_("pass")
print mail.stat()
print mail.list()
print ""

if mail.stat()[1] > 0:
    print "You have new mail."
else:
    print "No new mail."

print ""

numMessages = len(mail.list()[1])
for i in range(numMessages):
    for j in mail.retr(i+1)[1]:
        #print j
        msg = email.message_from_string(j) # new statement
        print(msg.get_payload()) # new statement

mail.quit()
input("Press any key to continue.")