BeautifulSoup HTML table parsing

Question

I am trying to parse information (html tables) from this site: http://www.511virginia.org/RoadConditions.aspx?j=All&r=1

Currently I am using BeautifulSoup and the code I have looks like this

from mechanize import Browser
from BeautifulSoup import BeautifulSoup

mech = Browser()

url = "http://www.511virginia.org/RoadConditions.aspx?j=All&r=1"
page = mech.open(url)

html = page.read()
soup = BeautifulSoup(html)

table = soup.find("table")

rows = table.findAll('tr')[3]

cols = rows.findAll('td')

roadtype = cols[0].string
start = cols.[1].string
end = cols[2].string
condition = cols[3].string
reason = cols[4].string
update = cols[5].string

entry = (roadtype, start, end, condition, reason, update)

print entry

The issue is with the start and end columns. They just get printed as "None"

Output:

(u'Rt. 613N (Giles County)', None, None, u'Moderate', u'snow or ice', u'01/13/2010 10:50 AM')

I know that they get stored in the columns list, but it seems that the extra link tag is messing up the parsing with the original html looking like this:

<td headers="road-type" class="ConditionsCellText">Rt. 613N (Giles County)</td>
<td headers="start" class="ConditionsCellText"><a href="conditions.aspx?lat=37.43036753&long=-80.51118005#viewmap">Big Stony Ck Rd; Rt. 635E/W (Giles County)</a></td>
<td headers="end" class="ConditionsCellText"><a href="conditions.aspx?lat=37.43036753&long=-80.51118005#viewmap">Cabin Ln; Rocky Mount Rd; Rt. 721E/W (Giles County)</a></td>
<td headers="condition" class="ConditionsCellText">Moderate</td>
<td headers="reason" class="ConditionsCellText">snow or ice</td>
<td headers="update" class="ConditionsCellText">01/13/2010 10:50 AM</td>

so what should be printed is:

(u'Rt. 613N (Giles County)', u'Big Stony Ck Rd; Rt. 635E/W (Giles County)', u'Cabin Ln; Rocky Mount Rd; Rt. 721E/W (Giles County)', u'Moderate', u'snow or ice', u'01/13/2010 10:50 AM')

Any suggestions or help is appreciated, and thank you in advance.

Answer 1

start = cols[1].find('a').string

or simpler

start = cols[1].a.string

or better

start = str(cols[1].find(text=True))

and

entry = [str(x) for x in cols.findAll(text=True)]