How to use pytest to check that Error is NOT raised

python pytest raise
paraklet picture paraklet · Nov 28, 2013 · Viewed 49.2k times · Source

Let's assume we have smth like that :

import py, pytest

ERROR1 = ' --- Error : value < 5! ---'
ERROR2 = ' --- Error : value > 10! ---'

class MyError(Exception):
    def __init__(self, m):
        self.m = m

    def __str__(self):
        return self.m

def foo(i):
    if i < 5:
        raise MyError(ERROR1)
    elif i > 10:
        raise MyError(ERROR2)
    return i


# ---------------------- TESTS -------------------------
def test_foo1():
    with pytest.raises(MyError) as e:
        foo(3)
    assert ERROR1 in str(e)

def test_foo2():
    with pytest.raises(MyError) as e:
        foo(11)
    assert ERROR2 in str(e)

def test_foo3():
        ....
        foo(7)
         ....

Q: How can I make test_foo3() to test, that no MyError is raised? It's obvious, that i could just test :

def test_foo3():
    assert foo(7) == 7

but i want to test that via pytest.raises(). Is is possible someway? For example: in a case, that function "foo" has no return-value at all,

def foo(i):
    if i < 5:
        raise MyError(ERROR1)
    elif i > 10:
        raise MyError(ERROR2)

it could make sense to test this way, imho.

Answer

Faruk Sahin picture Faruk Sahin · Nov 28, 2013

A test will fail if it raises any kind of unexpected Exception. You can just invoke foo(7) and you will have tested that no MyError is raised. So, following will suffice:

def test_foo3():
    foo(7)

If you want to be explicit and write an assert statement for this, you can do:

def test_foo3():
    try:
        foo(7)
    except MyError:
        pytest.fail("Unexpected MyError ..")

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