Python requests library how to pass Authorization header with single token

Question

I have a request URI and a token. If I use:

curl -s "<MY_URI>" -H "Authorization: TOK:<MY_TOKEN>"

etc., I get a 200 and view the corresponding JSON data. So, I installed requests and when I attempt to access this resource I get a 403 probably because I do not know the correct syntax to pass that token. Can anyone help me figure it out? This is what I have:

import sys,socket
import requests

r = requests.get('<MY_URI>','<MY_TOKEN>')
r. status_code

I already tried:

r = requests.get('<MY_URI>',auth=('<MY_TOKEN>'))
r = requests.get('<MY_URI>',auth=('TOK','<MY_TOKEN>'))
r = requests.get('<MY_URI>',headers=('Authorization: TOK:<MY_TOKEN>'))

But none of these work.

Answer 1

In python:

('<MY_TOKEN>')

is equivalent to

'<MY_TOKEN>'

And requests interprets

('TOK', '<MY_TOKEN>')

As you wanting requests to use Basic Authentication and craft an authorization header like so:

'VE9LOjxNWV9UT0tFTj4K'

Which is the base64 representation of 'TOK:<MY_TOKEN>'

To pass your own header you pass in a dictionary like so:

r = requests.get('<MY_URI>', headers={'Authorization': 'TOK:<MY_TOKEN>'})