Trying to use open(filename, 'w' ) gives IOError: [Errno 2] No such file or directory if directory doesn't exist

gonzalimator picture gonzalimator · Sep 12, 2013 · Viewed 94k times · Source

I am trying to create and write to a text file using Python. I have searched and cannot find a solution/reason for this error.

Here's the code that doesn't work:

afile = 'D:\\temp\\test.txt'
outFile = open(afile, 'w' )
outFile.write('Test.')
outFile.close()

# Error: 2
# Traceback (most recent call last):
#   File "<maya console>", line 1, in <module>
# IOError: [Errno 2] No such file or directory: 'D:\\temp\\test.txt' #

Most answers I found related to the slashes in the path, so...

I tried 'D:/temp/test.txt' and got an error.
I tried r'D:\temp\test.txt' and got an error.

When I try to create a file at the root of D:/ I have success.

'D:/test.txt' works.
'D:\\test.txt' works.
r'D:\test.txt' works.

It seems that I can't create the directory path I would like while trying to create the file. What is the correct method for creating files at a specific path with Python on Windows(7)? Am I misunderstanding what open() can do? Does it create directories if they don't exist or do I need to explicitly create the directory path before I use open() in 'write' mode to create a file?

Answer

David Heffernan picture David Heffernan · Sep 12, 2013

You are correct in surmising that the parent directory for the file must exist in order for open to succeed. The simple way to deal with this is to make a call to os.makedirs.

From the documentation:

os.makedirs(path[, mode])

Recursive directory creation function. Like mkdir(), but makes all intermediate-level directories needed to contain the leaf directory.

So your code might run something like this:

filename = ...
dirname = os.path.dirname(filename)
if not os.path.exists(dirname):
    os.makedirs(dirname)
with open(filename, 'w'):
    ...