I am trying to handle jira-python exception but my try, except does not seem to catch it. I also need to add more lines in order to be able to post this. So there they are, the lines.
try:
new_issue = jira.create_issue(fields=issue_dict)
stdout.write(str(new_issue.id))
except jira.exceptions.JIRAError:
stdout.write("JIRAError")
exit(1)
Here is the code that raises the exception:
import json
class JIRAError(Exception):
"""General error raised for all problems in operation of the client."""
def __init__(self, status_code=None, text=None, url=None):
self.status_code = status_code
self.text = text
self.url = url
def __str__(self):
if self.text:
return 'HTTP {0}: "{1}"\n{2}'.format(self.status_code, self.text, self.url)
else:
return 'HTTP {0}: {1}'.format(self.status_code, self.url)
def raise_on_error(r):
if r.status_code >= 400:
error = ''
if r.text:
try:
response = json.loads(r.text)
if 'message' in response:
# JIRA 5.1 errors
error = response['message']
elif 'errorMessages' in response and len(response['errorMessages']) > 0:
# JIRA 5.0.x error messages sometimes come wrapped in this array
# Sometimes this is present but empty
errorMessages = response['errorMessages']
if isinstance(errorMessages, (list, tuple)):
error = errorMessages[0]
else:
error = errorMessages
elif 'errors' in response and len(response['errors']) > 0:
# JIRA 6.x error messages are found in this array.
error = response['errors']
else:
error = r.text
except ValueError:
error = r.text
raise JIRAError(r.status_code, error, r.url)
I know I'm not answering the question, but I feel I need to warn people that could get confused by that code (as I did)... Maybe you are trying to write your own version of jira-python or it's an old version?
In any case, here the link to the jira-python code for the JIRAError class and here the list of codes
to catch the exception from that package I use the below code
from jira import JIRA, JIRAError
try:
...
except JIRAError as e:
print e.status_code, e.text