I have a program with a GUI that runs an external program through a Popen call:
p = subprocess.Popen("<commands>" , stdout=subprocess.PIPE , stderr=subprocess.PIPE , cwd=os.getcwd())
p.communicate()
But a console pops up, regardless of what I do (I've also tried passing it NUL for the file handle). Is there any way to do that without getting the binary I call to free its console?
From here:
import subprocess
def launchWithoutConsole(command, args):
"""Launches 'command' windowless and waits until finished"""
startupinfo = subprocess.STARTUPINFO()
startupinfo.dwFlags |= subprocess.STARTF_USESHOWWINDOW
return subprocess.Popen([command] + args, startupinfo=startupinfo).wait()
if __name__ == "__main__":
# test with "pythonw.exe"
launchWithoutConsole("d:\\bin\\gzip.exe", ["-d", "myfile.gz"])
Note that sometimes suppressing the console makes subprocess calls fail with "Error 6: invalid handle". A quick fix is to redirect stdin
, as explained here: Python running as Windows Service: OSError: [WinError 6] The handle is invalid