How to convert sparse matrix to dense form using python

Tiger1 picture Tiger1 · Aug 3, 2013 · Viewed 11.6k times · Source

I have the following matrix which I believe is sparse. I tried converting to dense using the x.dense format but it never worked. Any suggestions as to how to do this?, thanks.

mx=[[(0, 2), (1, 1), (2, 1), (3, 1), (4, 1), (5, 3), (6, 4), (7, 2), (8, 5), (9, 1)], 
[(10, 1), (11, 5), (12, 2), (13, 1), (21, 1), (22, 1), (23, 1), (24, 1), (25, 1), (26, 2)], 
[(27, 2), (28, 1), (29, 1), (30, 1), (31, 2), (32, 1), (33, 1), (34, 1), (35, 1), (36, 1)]]

someone put forward the solution below, but is there a better way?

def assign_coo_to_dense(sparse, dense):
    dense[sparse.row, sparse.col] = sparse.data

mx.todense(). Intended output should appear in this form:[[2,1,1,1,1,3,4], [1,5,2,1,1,1,1], [2,1,1,1,2,1,1,1]]

Answer

Akavall picture Akavall · Aug 4, 2013

List comprehension is the easiest way:

new_list = [[b for _,b in sub] for sub in mx]

Result:

>>> new_list
[[2, 1, 1, 1, 1, 3, 4, 2, 5, 1], [1, 5, 2, 1, 1, 1, 1, 1, 1, 2], [2, 1, 1, 1, 2, 1, 1, 1, 1, 1]]