IOError: [Errno 32] Broken pipe: Python

python python-3.x sigpipe
JOHANNES_NYÅTT picture JOHANNES_NYÅTT · Jan 8, 2013 · Viewed 202.7k times · Source

I have a very simple Python 3 script:

f1 = open('a.txt', 'r')
print(f1.readlines())
f2 = open('b.txt', 'r')
print(f2.readlines())
f3 = open('c.txt', 'r')
print(f3.readlines())
f4 = open('d.txt', 'r')
print(f4.readlines())
f1.close()
f2.close()
f3.close()
f4.close()

But it always says:

IOError: [Errno 32] Broken pipe

I saw on the internet all the complicated ways to fix this, but I copied this code directly, so I think that there is something wrong with the code and not Python's SIGPIPE.

I am redirecting the output, so if the above script was named "open.py", then my command to run would be:

open.py | othercommand

Answer

akhan picture akhan · May 31, 2013

The problem is due to SIGPIPE handling. You can solve this problem using the following code:

from signal import signal, SIGPIPE, SIG_DFL
signal(SIGPIPE,SIG_DFL)

See here for background on this solution. Better answer here.

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