I have a list of tuples like this:
[('foo','bar'),('foo1','bar1'),('foofoo','barbar')]
What is the fastest way in python (running on a very low cpu/ram machine) to swap values like this...
[('bar','foo'),('bar1','foo1'),('barbar','foofoo')]
I am currently using:
for x in mylist:
self.my_new_list.append(((x[1]),(x[0])))
Is there a better or faster way???
You could use map:
map (lambda t: (t[1], t[0]), mylist)
Or list comprehension:
[(t[1], t[0]) for t in mylist]
List comprehensions are preferred and supposedly much faster than map when lambda is needed, however note that list comprehension has a strict evaluation, that is it will be evaluated as soon as it gets bound to variable, if you're worried about memory consumption use a generator instead:
g = ((t[1], t[0]) for t in mylist)
#call when you need a value
g.next()
There are some more details here: Python List Comprehension Vs. Map