I've started programming today and have this issue with Python. It's pretty dumb but I can't figure out how to do it. When I use the print command, it prints whatever I want and then goes to a different line. For example:
print "this should be"; print "on the same line"
Should return:
this should be on the same line
but instead returns:
this should be
on the same line
More precisely I was trying to create a program with if
that told me whether a number was a 2 or not
def test2(x):
if x == 2:
print "Yeah bro, that's tottaly a two"
else:
print "Nope, that is not a two. That is a (x)"
But it doesn't recognise the last (x)
as the value entered, and rather prints exactly: "(x)" (the letter with the brackets). To make it work I have to write:
print "Nope, that is not a two. That is a"; print (x)
And if e.g. I enter test2(3)
that gives:
Nope, that is not a two, that is a
3
So either i need to make Python recognise my (x) inside a print line as the number; or to print two separate things but on the same line. Thanks in advance and sorry for such a stupid question.
IMPORTANT NOTE: I am using version 2.5.4
Another note: If i put print "Thing" , print "Thing2"
it says "Syntax error" on the 2nd print.
In Python 3.x, you can use the end
argument to the print()
function to prevent a newline character from being printed:
print("Nope, that is not a two. That is a", end="")
In Python 2.x, you can use a trailing comma:
print "this should be",
print "on the same line"
You don't need this to simply print a variable, though:
print "Nope, that is not a two. That is a", x
Note that the trailing comma still results in a space being printed at the end of the line, i.e. it's equivalent to using end=" "
in Python 3. To suppress the space character as well, you can either use
from __future__ import print_function
to get access to the Python 3 print function or use sys.stdout.write()
.