iterating over a range of rows using ws.iter_rows in the optimised reader of openpyxl

Question

I need to read an xlsx file of 10x5324 cells

This is the gist of what i was trying to do:

from openpyxl import load_workbook
filename = 'file_path'

wb = load_workbook(filename)
ws = wb.get_sheet_by_name('LOG')

col = {'Time':0 ...}

for i in ws.columns[col['Time']][1:]:
    print i.value.hour

The code was taking much too long to run then it should (I was performing operations, not printing) and after a while I got impatient and cancelled it.

Any idea how I can work it in the optimized reader? I need to iterate over a range of rows, not over all rows. This is what i tried, but it's wrong:

wb = load_workbook(filename, use_iterators = True)
ws = wb.get_sheet_by_name('LOG')
for i in ws.iter_rows[1:]:
    print i[col['Time']].value.hour

Is there any way I can do it without the range function?

I guess one way to do it would be:

for i in ws.iter_rows[1:]:
    if i.row == startrow:
        continue
    print i[col['Time']].value.hour
    if i.row == endrow:
        break

but is there a more elegant solution? (that doesn't work either btw)

Answer 1

The simplest solution with a lower bound would be something like this:

# Your code:
from openpyxl import load_workbook
filename = 'file_path'
wb = load_workbook(filename, use_iterators=True)
ws = wb.get_sheet_by_name('LOG')

# Solution 1:
for row in ws.iter_rows(row_offset=1):
    # code to execute per row...

Here another way to execute what you describe, with the enumerate function:

# Solution 2:
start, stop = 1, 100    # This will allow you to set a lower and upper limit
for index, row in enumerate(ws.iter_rows()):
    if start < index < stop:
        # code to execute per row...

The index variable keeps count of what row you are on, so it can be used in place of range or xrange. This method is pretty straightforward and works with iterators unlike range or slicing, and can be used with just the lower bound too, if desired. Cheers!