Difference between type(obj) and obj.__class__

Question

What is the difference between type(obj) and obj.__class__? Is there ever a possibility of type(obj) is not obj.__class__?

I want to write a function that works generically on the supplied objects, using a default value of 1 in the same type as another parameter. Which variation, #1 or #2 below, is going to do the right thing?

def f(a, b=None):
  if b is None:
    b = type(a)(1) # #1
    b = a.__class__(1) # #2

Answer 1

This is an old question, but none of the answers seems to mention that. in the general case, it IS possible for a new-style class to have different values for type(instance) and instance.__class__:

class ClassA(object):
    def display(self):
        print("ClassA")

class ClassB(object):
    __class__ = ClassA

    def display(self):
        print("ClassB")

instance = ClassB()

print(type(instance))
print(instance.__class__)
instance.display()

Output:

<class '__main__.ClassB'>
<class '__main__.ClassA'>
ClassB

The reason is that ClassB is overriding the __class__ descriptor, however the internal type field in the object is not changed. type(instance) reads directly from that type field, so it returns the correct value, whereas instance.__class__ refers to the new descriptor replacing the original descriptor provided by Python, which reads the internal type field. Instead of reading that internal type field, it returns a hardcoded value.