An integer is required? open()

Question

I have a very simple python script that should scan a text file, which contains lines formatted as id='value' and put them into a dict. the python module is called chval.py and the input file is in.txt. here's the code:

import os,sys
from os import *
from sys import *

vals = {}

f = open(sys.argv[1], 'r')

for line in val_f:
    t = line.split('=')
    t[1].strip('\'')
    vals.append(t[0], t[1])

print vals

f.close()

when i try to run it i get:

Traceback (most recent call last):
File "chval.py", line 9, in ? f = open(sys.argv[1], 'r') TypeError: an integer is required

I'm using python 2.4... because i've been challenged to not use anything newer, is there something about open() that I don't know about? Why does it want an integer?

anything after that line is untested. in short: why is it giving me the error and how do i fix it?

Answer 1

Because you did from os import *, you are (accidenally) using os.open, which indeed requires an integer flag instead of a textual "r" or "w". Take out that line and you'll get past that error.