The Python requests module provides good documentation on how to upload a single file in a single request:
files = {'file': open('report.xls', 'rb')}
I tried extending that example by using this code in an attempt to upload multiple files:
files = {'file': [open('report.xls', 'rb'), open('report2.xls, 'rb')]}
but it resulted in this error:
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib.py", line 1052, in splittype
match = _typeprog.match(url)
TypeError: expected string or buffer
Is it possible to upload a list of files in a single request using this module, and how?
To upload a list of files with the same key value in a single request, you can create a list of tuples with the first item in each tuple as the key value and the file object as the second:
files = [('file', open('report.xls', 'rb')), ('file', open('report2.xls', 'rb'))]