I'm trying to build a bot which automatically sends a message whenever there is an update in the latest news using python. Following is what I did.
companies = {
"name_1": {
"rss": "name_1 rss link",
"link": "name_1 link"
}
}
import feedparser as fp
import time, telebot
token = <TOKEN>
bot = telebot.TeleBot(token)
LIMIT = 1
while True:
def get_news():
count = 1
news = []
for company, value in companies.items():
count = 1
if 'rss' in value:
d = fp.parse(value['rss'])
for entry in d.entries:
if hasattr(entry, 'published'):
if count > LIMIT:
break
news.append(entry.link)
count = count + 1
return (news)
val = get_news()
time.sleep(10)
val2 = get_news()
try:
if val[0]!=val2[0]:
bot.send_message(chat_id= "Hardcoded chat_id", text=val2[0])
except Exception:
pass
How can I update my code so that the bot publishes the latest news to all the groups to which it is added?
I got the chat_id using:
bot.get_updates()[-1].message.chat.id
Any suggestions on how to automate this?
Using the python-telegram-bot api, you can send a message like this
bot.send_message(id, text='Message')
you need the "bot" and "id"
I keep these in a dictionary called "mybots" which I fill/update when people interact with the bot for the first time / or on later communication with the bot. It's possible to pickle this dictionary to keep it persistant.
mybots = {}
def start(bot, update):
"""Send a message when the command /start is issued."""
mybots[update.message.chat_id] = bot
update.message.reply_text('Hello{}!'.format(
update.effective_chat.first_name))
def send_later():
for id, bot in mybots.items():
bot.send_message(id, text='Beep!')