I have a directory structure & build.xml like this
/path-to-project/src/prj1
/path-to-project/src/prj2
/path-to-project/tests
/path-to-project/tests/build.xml
I have to somehow get the path
/path-to-project/
in my build.xml
My build.xml is like this
<project name="php-project-1" default="build" basedir=".">
<property name="source" value="src"/>
<target name="phploc" description="Generate phploc.csv">
<exec executable="phploc">
<arg value="--log-csv" />
<arg value="${basedir}/build/logs/phploc.csv" />
<arg path="${source}" />
</exec>
</target>
</project>
Here I somehow want to get value of ${source}
as /path-to-project/src/
but I am not getting it with ${parent.dir}
Is it possible to get this path in the build.xml?
You can use ..
just as you do on the command-line to navigate to the parent directory.
<project name="php-project-1" default="build" basedir=".">
<property name="root.dir" location=".."/>
<property name="source" location="${root.dir}/src"/>
...
</project>
Update: Changed value
to location
as per martin's answer which you should accept.