I have this:
list($firstname, $lastname) = explode(' ', $queryString);
Sometiems $lastname does not gets defined, and it's there i am getting undefined offset error.
Because it can not find anything to put in $lastname, i guess.
After the explode() i have:
if(!$lastname) { $lastname = $firstname; }
So my question is how can i define it as the $firstname if $lastname is not defined (if you wrote only 'Adam' and not 'Adam Thompson', the lastname should be defined so it is 'Adam Adam')
It does this for me now, but I am receiving the offset error
Answer
list($firstname, $lastname) = array_pad(explode(' ', $queryString, 2), 2, null);
The 2 in explode() ensures, that there are at most 2 values and array_pad() ensures, that there are at least 2 values. If there is no space character , $lastname is null. This you can use to decide what comes next
$lastname = is_null($lastname) ? $firstname : $lastname;
Little update: For this specific case you can use a little trick
list($firstname, $lastname) = array_pad(explode(' ', $queryString, 2), 2, $queryString);
This will do all that in one step. It should work, because
- There is always at least one value (for
$firstname) - If there is one value, then
$queryString == $firstname. Thats now the value that is used to fill the array up to 2 values (which is exactly one, because one value we already have) - If there are two values, then the array is not filled with
$queryString, because we already have 2 values
At least for readability I would prefer the first more obvious solution.