Named backreferences with preg_replace

Dan Lugg picture Dan Lugg · Mar 10, 2011 · Viewed 7.4k times · Source

Pretty straightforward; I can't seem to find anything definitive regarding PHP's preg_replace() supporting named backreferences:

// should match, replace, and output: user/profile/foo
$string = 'user/foo';
echo preg_replace('#^user/(?P<id>[^/]+)$#Di', 'user/profile/(?P=id)', $string);

This is a trivial example, but I'm wondering if this syntax, (?P=name) is simply not supported. Syntactical issue, or non-existent functionality?

Answer

Dimitry picture Dimitry · Mar 10, 2011

They exist:

http://www.php.net/manual/en/regexp.reference.back-references.php

With preg_replace_callback:

function my_replace($matches) {
    return '/user/profile/' . $matches['id'];
}
$newandimproved = preg_replace_callback('#^user/(?P<id>[^/]+)$#Di', 'my_replace', $string);

Or even quicker

$newandimproved = preg_replace('#^user/([^/]+)$#Di', '/user/profile/$1', $string);