I know that I can create a PHP stream from a filename (a real one, or an URL), by using the fopen function:
$stream = fopen('php://temp', 'r');
The resulting stream ($stream
) is then a resource of type "stream", created from the URL php://temp
.
But how I can create a stream like the above from a resource?
Why am I asking this?
I am working on a PSR-7 library and I implemented the PSR-7 StreamInterface with a Stream
class. In order to create Stream
instances, I decided to implement a StreamFactory
too. Its interface, StreamFactoryInterface
, is defined in the PSR-17 (HTTP Factories) proposal.
The StreamFactoryInterface
defines a method named createStreamFromResource
, which - conform to its official comments - should:
Create a new stream from an existing resource.
The stream MUST be readable and may be writable.
So the factory method receives a resource as argument. And, in its concrete implementation, a new Stream
object is created - which receives a resource as argument, too.
Here is the problem:
For the sake of simplicity, let's say that the Stream
class works only with a stream, e.g. with a resource of type "stream". If it receives a resource which is not of type "stream", it rejects it.
So, what if the resource argument of createStreamFromResource
is not already a resource of type "stream"? How can I transform it into a stream, e.g. into a resource of type "stream", so that I can pass it further, to the call for creating a new Stream
object with it? Is there a way (a PHP method, a function, or maybe a casting function) of achieving this task?
Notes:
testStream.php
) of how I create a stream, e.g. a Stream
instance, in three ways: once directly, and twice using the stream factory.StreamFactory
with the method createStreamFromResource
. A call to this method should be my fourth way of creating a stream in testStream.php
.Stream
and Response
, so that you can directly test all, if you wish. The two classes are a very simplified version of my real code.Thank you very much for your time and patience!
<?php
use Tests\Stream;
use Tests\Response;
use Tests\StreamFactory;
/*
* ================================================
* Option 1: Create a stream by a stream name
* (like "php://temp") with read and write rights.
* ================================================
*/
$stream = new Stream('php://temp', 'w+b');
$response = new Response($stream);
$response->getBody()->write(
'Stream 1: Created directly.<br/><br/>'
);
echo $response->getBody();
/*
* ================================================
* Option 2: Create a stream by a stream name
* (like "php://temp"), using a stream factory.
* ================================================
*/
$streamFactory = new StreamFactory();
$stream = $streamFactory->createStreamFromFile('php://temp', 'w+b');
$response = new Response($stream);
$response->getBody()->write(
'Stream 2: Created by a stream name, with a stream factory.<br/><br/>'
);
echo $response->getBody();
/*
* ================================================
* Option 3: Create a stream from a string, using a
* stream factory.
* ================================================
*/
$streamFactory = new StreamFactory();
$stream = $streamFactory->createStream(
'Stream 3: Created from a string, with a stream factory.<br/><br/>'
);
$response = new Response($stream);
echo $response->getBody();
/*
* ================================================
* Option 4: Create a stream from an existing
* resource, using a stream factory.
* ================================================
*
* @asking How can I create a stream by calling the
* the factory method ServerFactory::createStreamFromResource
* with a resource which is not of type "stream"?
*/
//...
<?php
namespace Tests;
use Tests\Stream;
use Psr\Http\Message\StreamInterface;
use Psr\Http\Message\StreamFactoryInterface;
class StreamFactory implements StreamFactoryInterface {
/**
* Create a new stream from an existing resource.
*
* The stream MUST be readable and may be writable.
*
* @param resource $resource
*
* @return StreamInterface
* @throws \InvalidArgumentException
*/
public function createStreamFromResource($resource) {
/*
* @asking What if $resource is not already a resource of type *"stream"*?
* How can I transform it into a stream, e.g. into a resource of type *"stream"*,
* so that I can pass it further, to the call for creating a new `Stream` object
* with it? Is there a way (a PHP method, a function, or maybe a casting function)
* of achieving this task?
*/
//...
return new Stream($resource, 'w+b');
}
/**
* Create a new stream from a string.
*
* The stream SHOULD be created with a temporary resource.
*
* @param string $content
*
* @return StreamInterface
* @throws \InvalidArgumentException
*/
public function createStream($content = '') {
if (!isset($content) || !is_string($content)) {
throw new \InvalidArgumentException('For creating a stream, a content string must be provided!');
}
$stream = $this->createStreamFromFile('php://temp', 'w+b');
$stream->write($content);
return $stream;
}
/**
* Create a stream from an existing file.
*
* The file MUST be opened using the given mode, which may be any mode
* supported by the `fopen` function.
*
* The `$filename` MAY be any string supported by `fopen()`.
*
* @param string $filename
* @param string $mode
*
* @return StreamInterface
*/
public function createStreamFromFile($filename, $mode = 'r') {
return new Stream($filename, $mode);
}
}
<?php
namespace Tests;
use Psr\Http\Message\StreamInterface;
class Stream implements StreamInterface {
/**
* Stream (resource).
*
* @var resource
*/
private $stream;
/**
*
* @param string|resource $stream Stream name, or resource.
* @param string $accessMode (optional) Access mode.
* @throws \InvalidArgumentException
*/
public function __construct($stream, string $accessMode = 'r') {
if (
!isset($stream) ||
(!is_string($stream) && !is_resource($stream))
) {
throw new \InvalidArgumentException(
'The provided stream must be a filename, or an opened resource of type "stream"!'
);
}
if (is_string($stream)) {
$this->stream = fopen($stream, $accessMode);
} elseif (is_resource($stream)) {
if ('stream' !== get_resource_type($stream)) {
throw new \InvalidArgumentException('The provided resource must be of type "stream"!');
}
$this->stream = $stream;
}
}
/**
* Write data to the stream.
*
* @param string $string The string that is to be written.
* @return int Returns the number of bytes written to the stream.
* @throws \RuntimeException on failure.
*/
public function write($string) {
return fwrite($this->stream, $string);
}
/**
* Reads all data from the stream into a string, from the beginning to end.
*
* @return string
*/
public function __toString() {
try {
// Rewind the stream.
fseek($this->stream, 0);
// Get the stream contents as string.
$contents = stream_get_contents($this->stream);
return $contents;
} catch (\RuntimeException $exc) {
return '';
}
}
public function close() {}
public function detach() {}
public function eof() {}
public function getContents() {}
public function getMetadata($key = null) {}
public function getSize() {}
public function isReadable() {}
public function isSeekable() {}
public function isWritable() {}
public function read($length) {}
public function rewind() {}
public function seek($offset, $whence = SEEK_SET) {}
public function tell() {}
}
<?php
namespace Tests;
use Psr\Http\Message\StreamInterface;
use Psr\Http\Message\ResponseInterface;
class Response implements ResponseInterface {
/**
*
* @param StreamInterface $body Message body.
*/
public function __construct(StreamInterface $body) {
$this->body = $body;
}
/**
* Gets the body of the message.
*
* @return StreamInterface Returns the body as a stream.
*/
public function getBody() {
return $this->body;
}
public function getHeader($name) {}
public function getHeaderLine($name) {}
public function getHeaders() {}
public function getProtocolVersion() {}
public function hasHeader($name) {}
public function withAddedHeader($name, $value) {}
public function withBody(StreamInterface $body) {}
public function withHeader($name, $value) {}
public function withProtocolVersion($version) {}
public function withoutHeader($name) {}
public function getReasonPhrase() {}
public function getStatusCode() {}
public function withStatus($code, $reasonPhrase = '') {}
}
You can implement it any way you like but this method is essentially just a wrapper for a pre-generated resource.
In most cases, your Stream is probably going to take in a string and possibly a settings/options array and create a stream from the information (possibly with an fopen('http://...')
somewhere along the way.
The createStreamFromResource($resource) would take in a pre-generated resource (e.g. the return resource value from an fopen
rather than the data to execute the fopen
):
class Stream implements StreamInterface {
// ...
public function __construct($url, $opt = null) {
// ...
if( is_resource( $url ) ) {
/*
* Check that the $resource is a valid resource
* (e.g. an http request from an fopen call vs a mysql resource.)
* or possibly a stream context that still needs to create a
* request...
*/
if( !$isValid ) {
return false;
}
$this->resource = $resource;
} else {
// ...
$this->resource = fopen($url, $modifiedOpt);
// ...
}
}
// ...
/* createStreamFromResource would call Stream::fromResource($r)
* or possibly Stream($resource) directly, your call.
*/
static function fromResource($resource) {
return new static($resource);
}
}
Your factory method could be something as simple as:
public function createStreamFromResource($resource) {
return Stream::fromResource($resource);
}