It is well documented that PHP5 OOP objects are passed by reference by default. If this is by default, it seems to me there is a no-default way to copy with no reference, how??
function refObj($object){
foreach($object as &$o){
$o = 'this will change to ' . $o;
}
return $object;
}
$obj = new StdClass;
$obj->x = 'x';
$obj->y = 'y';
$x = $obj;
print_r($x)
// object(stdClass)#1 (3) {
// ["x"]=> string(1) "x"
// ["y"]=> string(1) "y"
// }
// $obj = refObj($obj); // no need to do this because
refObj($obj); // $obj is passed by reference
print_r($x)
// object(stdClass)#1 (3) {
// ["x"]=> string(1) "this will change to x"
// ["y"]=> string(1) "this will change to y"
// }
At this point I would like $x
to be the original $obj
, but of course it's not. Is there any simple way to do this or do I have to code something like this
<?php
$x = clone($obj);
So it should read like this:
<?php
function refObj($object){
foreach($object as &$o){
$o = 'this will change to ' . $o;
}
return $object;
}
$obj = new StdClass;
$obj->x = 'x';
$obj->y = 'y';
$x = clone($obj);
print_r($x)
refObj($obj); // $obj is passed by reference
print_r($x)