I realise I can do this with CURL very easily, but I was wondering if it was possible to use file_get_contents()
with the http stream context to upload a file to a remote web server, and if so, how?
First of all, the first rule of multipart
Content-Type is to define a boundary that will be used as a delimiter between each part (because as the name says, it can have multiple parts). The boundary can be any string that is not contained in the content body. I will usually use a timestamp:
define('MULTIPART_BOUNDARY', '--------------------------'.microtime(true));
Once your boundary is defined, you must send it with the Content-Type
header to tell the webserver what delimiter to expect:
$header = 'Content-Type: multipart/form-data; boundary='.MULTIPART_BOUNDARY;
Once that is done, you must build a proper content body that matches the HTTP specification and the header you sent. As you know, when POSTing a file from a form, you will usually have a form field name. We'll define it:
// equivalent to <input type="file" name="uploaded_file"/>
define('FORM_FIELD', 'uploaded_file');
Then we build the content body:
$filename = "/path/to/uploaded/file.zip";
$file_contents = file_get_contents($filename);
$content = "--".MULTIPART_BOUNDARY."\r\n".
"Content-Disposition: form-data; name=\"".FORM_FIELD."\"; filename=\"".basename($filename)."\"\r\n".
"Content-Type: application/zip\r\n\r\n".
$file_contents."\r\n";
// add some POST fields to the request too: $_POST['foo'] = 'bar'
$content .= "--".MULTIPART_BOUNDARY."\r\n".
"Content-Disposition: form-data; name=\"foo\"\r\n\r\n".
"bar\r\n";
// signal end of request (note the trailing "--")
$content .= "--".MULTIPART_BOUNDARY."--\r\n";
As you can see, we're sending the Content-Disposition
header with the form-data
disposition, along with the name
parameter (the form field name) and the filename
parameter (the original filename). It is also important to send the Content-Type
header with the proper MIME type, if you want to correctly populate the $_FILES[]['type']
thingy.
If you had multiple files to upload, you just repeat the process with the $content bit, with of course, a different FORM_FIELD
for each file.
Now, build the context:
$context = stream_context_create(array(
'http' => array(
'method' => 'POST',
'header' => $header,
'content' => $content,
)
));
And execute:
file_get_contents('http://url/to/upload/handler', false, $context);
NOTE: There is no need to encode your binary file before sending it. HTTP can handle binary just fine.