PHP: on select change, post form to self
It's basically what the title says.. I have a form with a select control that I want to force the form to post back to self on change.
$bmsclientlist = $clientobj->getBMSClientList();
echo '<form name="changebmsid" method="post" action="' . $_SERVER['PHP_SELF'] . '"><select name="bmsid">';
foreach($bmsclientlist as $bmsclient) {
$var = '';
if($client['bmsid'] == $bmsclient['id']) {
$var = ' selected="selected"';
}
echo '<option value="' . $bmsclient['id'] .'"'. $var .'>' .$bmsclient['clientname'] . '</option>';
}
echo '</select></form>';
$backupobj = new AdminBackup();
if(isset($_POST['bmsid']){
$statusarray = $backupobj->getStatusTotalsbyId($_POST['bmsid']);
}else{
$statusarray = $backupobj->getStatusTotals();
}
I know it's going to involve some javascript but I'm not too sure how to achieve this.
Any help most appreciated!
Thanks,
Jonesy
Answer
This is a <select> that will submit the parent form
<form method="post" action="#" name="myform">
<select name="x" onchange="myform.submit();">
<option value="y">y</option>
<option value="z">z</option>
</select>
</form>
All you have to do is give a name to your <form> and add the onchange event to your <select>...
Adam is right. While the example above works perfectly, I would do it like this:
Using jQuery but there are many other options available...
<head>
<script type="text/javascript" src="jquery.js"></script>
<script>
$(document).ready(function(){
$('#mySelect').change(function(){
myform.submit();
});
});
</script>
</head>
and the form
<body>
<form method="post" action="" name="myform">
<select name="x" id="mySelect">
<option value="y">y</option>
<option value="z">z</option>
</select>
</form>
</body>