I've learn a while ago on StackOverflow that we can get the "instance ID" of any resource, for instance:
var_dump(intval(curl_init())); // int(2)
var_dump(intval(finfo_open())); // int(3)
var_dump(intval(curl_init())); // int(4)
var_dump(intval(finfo_open())); // int(5)
var_dump(intval(curl_init())); // int(6)
I need something similar but applied to classes:
class foo {
public function __construct() {
ob_start();
var_dump($this); // object(foo)#INSTANCE_ID (0) { }
echo preg_replace('~.+#(\d+).+~s', '$1', ob_get_clean());
}
}
$foo = new foo(); // 1
$foo2 = new foo(); // 2
The above works but I was hoping for a faster solution or, at least, one that didn't involve output buffers. Please note that this won't necessarily be used within the constructor or even inside the class itself!
spl_object_hash()
is not what I'm looking for because the two objects produce identical hashes
The question previously contained an incorrect example of spl_object_hash
output; ensuring that both objects exist at the same time produces hashes which are subtly different:
var_dump(spl_object_hash($foo)); // 0000000079e5f3b60000000042b31773
var_dump(spl_object_hash($foo2)); // 0000000079e5f3b50000000042b31773
Casting to int like resources doesn't seem to work for objects:
Notice: Object of class foo could not be converted to int.
Is there a quick way to grab the same output without using object properties?
Besides var_dump()
, I've discovered by trial and error that debug_zval_dump()
also outputs the object instance, unfortunately it also needs output buffering since it doesn't return the result.
spl_object_hash()
could help you out here. It
returns a unique identifier for the object
which is always the same for a given instance.
EDIT after OP comment:
You could implement such a behavior using a static class property, e.g:
class MyClass
{
private static $_initialized = false;
public function __construct()
{
if (!self::$_initialized) {
self::$_initialized = true;
// your run-only-once code
}
}
}
But actually this has nothing to with your original question.