How can I handle the warning of file_get_contents() function in PHP?

Waseem picture Waseem · Nov 7, 2008 · Viewed 330.6k times · Source

I wrote a PHP code like this

$site="http://www.google.com";
$content = file_get_content($site);
echo $content;

But when I remove "http://" from $site I get the following warning:

Warning: file_get_contents(www.google.com) [function.file-get-contents]: failed to open stream:

I tried try and catch but it didn't work.

Answer

Roel picture Roel · Nov 7, 2008

Step 1: check the return code: if($content === FALSE) { // handle error here... }

Step 2: suppress the warning by putting an error control operator (i.e. @) in front of the call to file_get_contents(): $content = @file_get_contents($site);