I am trying to learn PHP classes so I can begin coding more OOP projects. To help me learn I am building a class that uses the Rapidshare API. Here's my class:
<?php
class RS
{
public $baseUrl = 'http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=';
function apiCall($params)
{
echo $baseUrl;
}
}
?>
$params
will contain a set of key pair values, like this:
$params = array(
'sub' => 'listfiles_v1',
'type' => 'prem',
'login' => '746625',
'password' => 'not_my_real_pass',
'realfolder' => '0',
'fields' => 'filename,downloads,size',
);
Which will later be appended to $baseUrl
to make the final request URL, but I can't get $baseUrl to appear in my apiCall()
method. I have tried the following:
var $baseUrl = 'http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=';
$baseUrl = 'http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=';
private $baseUrl = 'http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=';
And even tried $this->baseUrl = $baseUrl;
in my apiCall()
methid, I don't know what the hell I was thinking there though lol.
Any help is appreciated thanks :)
Try
class RS {
public $baseUrl = 'http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=';
function apiCall($params) {
echo $this->baseUrl;
}
}
I trust you are calling this code like so?
$rs = new RS;
$rs->apiCall($params);
Class attributes need to be prefixed with $this
in PHP. The only exceptions are static methods and class constants when you use self
.