ereg_replace to preg_replace?

Question

How can I convert

ereg_replace(".*\.(.*)$","\\1",$imgfile);

to

preg_replace... ?

?

I'm having trouble with it?

Answer 1

You should know 4 main things to port ereg patterns to preg:

1. Add delimiters(/): 'pattern' => '/pattern/'

2. Escape delimiter if it is a part of the pattern: 'patt/ern' => '/patt\/ern/'
   Achieve it programmatically in following way:
   $ereg_pattern = '<div>.+</div>';
$preg_pattern = '/' .addcslashes($ereg_pattern, '/') . '/';

3. eregi(case-insensitive matching): 'pattern' => '/pattern/i' So, if you are using eregi function for case insenstive matching, just add 'i' in the end of new pattern('/pattern/').

4. ASCII values: In ereg, if you use number in the pattern, it is assumed that you are referring to the ASCII of a character. But in preg, number is not treated as ASCII value. So, if your pattern contain ASCII value in the ereg expression(for example: new line, tabs etc) then convert it to hexadecimal and prefix it with \x.
   Example: 9(tab) becomes \x9 or alternatively use \t.

Hope this will help.