How can I explode the following string:
Lorem ipsum "dolor sit amet" consectetur "adipiscing elit" dolor
into
array("Lorem", "ipsum", "dolor sit amet", "consectetur", "adipiscing elit", "dolor")
So that the text in quotation is treated as a single word.
Here's what I have for now:
$mytext = "Lorem ipsum %22dolor sit amet%22 consectetur %22adipiscing elit%22 dolor"
$noquotes = str_replace("%22", "", $mytext");
$newarray = explode(" ", $noquotes);
but my code divides each word into an array. How do I make words inside quotation marks treated as one word?
You could use a preg_match_all(...)
:
$text = 'Lorem ipsum "dolor sit amet" consectetur "adipiscing \\"elit" dolor';
preg_match_all('/"(?:\\\\.|[^\\\\"])*"|\S+/', $text, $matches);
print_r($matches);
which will produce:
Array
(
[0] => Array
(
[0] => Lorem
[1] => ipsum
[2] => "dolor sit amet"
[3] => consectetur
[4] => "adipiscing \"elit"
[5] => dolor
)
)
And as you can see, it also accounts for escaped quotes inside quoted strings.
EDIT
A short explanation:
" # match the character '"'
(?: # start non-capture group 1
\\ # match the character '\'
. # match any character except line breaks
| # OR
[^\\"] # match any character except '\' and '"'
)* # end non-capture group 1 and repeat it zero or more times
" # match the character '"'
| # OR
\S+ # match a non-whitespace character: [^\s] and repeat it one or more times
And in case of matching %22
instead of double quotes, you'd do:
preg_match_all('/%22(?:\\\\.|(?!%22).)*%22|\S+/', $text, $matches);