PHP, get file name without file extension

Mostafa Elkady picture Mostafa Elkady · Feb 2, 2010 · Viewed 298.3k times · Source

I have this PHP code:

function ShowFileExtension($filepath)
{
    preg_match('/[^?]*/', $filepath, $matches);
    $string = $matches[0];

    $pattern = preg_split('/\./', $string, -1, PREG_SPLIT_OFFSET_CAPTURE);

    if(count($pattern) > 1)
    {
        $filenamepart = $pattern[count($pattern)-1][0];
        preg_match('/[^?]*/', $filenamepart, $matches);
        return strtolower($matches[0]);
    }
}

If I have a file named my.zip, this function returns .zip.

I want to do the reverse, I want the function to return my without the extension.

The file is just a string in a variable.

Answer

anon picture anon · Feb 2, 2010

No need for all that. Check out pathinfo(), it gives you all the components of your path.

Example from the manual:

$path_parts = pathinfo('/www/htdocs/index.html');

echo $path_parts['dirname'], "\n";
echo $path_parts['basename'], "\n";
echo $path_parts['extension'], "\n";
echo $path_parts['filename'], "\n"; // filename is only since PHP 5.2.0

Output of the code:

/www/htdocs
index.html
html
index

And alternatively you can get only certain parts like:

echo pathinfo('/www/htdocs/index.html', PATHINFO_EXTENSION); // outputs html