I'm using Doctrine's querybuilder in Symfony2 to create a query to fetch entities.
My current code looks like this:
$repository = $this->getDoctrine()->getRepository('AaaBundle:Application');
$queryBuilder = $repository->createQueryBuilder('a');
$queryBuilder
->addSelect('u')
->addSelect('i')
->orderBy('a.created_date', 'DESC')
->leftJoin('a.created_by', 'u')
->leftJoin('a.installations', 'i')
//->where('i.page = :page')
//->setParameter('page', $found)
;
Now I can use this to get all the pages regardless of them having an installation or not.
But I only want to join them it the $found
page is available (so that if there is an installation for the app, but it's on another page, the installation wont be joined). If I unquote the where clause, it will show only apps that have an installation for the page. I want all apps with or without installations for the page.
In SQL I can get this by adding AND
to the join
LEFT JOIN installations i ON a.id = i.app AND i.page = :page
This way I get the installation info for an app that has an installation on the page, but I get null values on the columns for app's that have installations on other pages or not at all.
Is there a way to do this in Doctrine or am I better off just getting all the installations for each application and then checking against the found page with php?
You can try this :
use Doctrine\ORM\Query\Expr;
->leftJoin('a.installations', 'i', Expr\Join::WITH, 'i.page = :page')
->setParameter('page', $page)
See function leftJoin in doc: http://docs.doctrine-project.org/projects/doctrine-orm/en/latest/reference/query-builder.html#high-level-api-methods