PHP preg_replace non-greedy trouble

php regex regex-greedy
Jeff Lamb picture Jeff Lamb · Dec 14, 2009 · Viewed 10k times · Source

I've been using the following site to test a PHP regex so I don't have to constantly upload: http://www.spaweditor.com/scripts/regex/index.php

I'm using the following regex:

/(.*?)\.{3}/

on the following string (replacing with nothing):

Non-important data...important data...more important data

and preg_replace is returning:

more important data

yet I expect it to return:

important data...more important data

I thought the ? is the non-greedy modifier. What's going on here?

Answer

Asaph picture Asaph · Dec 14, 2009

Your non-greedy modifier is working as expected. But preg_match replaces all occurences of the the (non-greedy) match with the replacement text ("" in your case). If you want only the first one replaced, you could pass 1 as the optional 4th argument (limit) to preg_replace function (PHP docs for preg_replace). On the website you linked, this can be accomplished by typing 1 into the text input between the word "Flags" and the word "limit".

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