I am working around fetch image URL from database & show image in php like following
<?php
$row['blog_url'] = "http://www.nasa.gov/images/content/711375main_grail20121205_4x3_946-710.jpg";
<img src="<?php echo $row['blog_url']; ?>" height="200" width="200" alt="image"/>
?>
but i want display no_imgae.jpeg if image not getting loaded from specified url as blog_url
if there any way to find out image is exist or not in php
thanks in advance...
This function will solve your problem :
function checkRemoteFile($url)
{
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
// don't download content
curl_setopt($ch, CURLOPT_NOBODY, 1);
curl_setopt($ch, CURLOPT_FAILONERROR, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
if(curl_exec($ch)!==FALSE)
{
return true;
}
else
{
return false;
}
}
Just pass the image url
in this function
and it will return yes
if image exists otherwise false