php how to go one level up on dirname(__FILE__)

php dirname
aVC picture aVC · Jun 19, 2012 · Viewed 115.7k times · Source

I have a folder structure as follows:

mydomain.com
  ->Folder-A
  ->Folder-B

I have a string from Database that is '../Folder-B/image1.jpg', which points to an image in Folder-B.

Inside a script in Folder-A, I am using dirname(FILE) to fetch the filename and I get mydomain.com/Folder-A. Inside this script, I need to get a string that says 'mydomain.com/Folder-B/image1.jpg. I tried 

$path=dirname(__FILE__).'/'.'../Folder-B/image1.jpg';

This shows up as mydomain.com%2FFolder-A%2F..%2FFolder-B%2Fimage1.jpg

This is for a facebook share button, and this fails to fetch the correct image. Anyone know how to get the path correctly?

Edit: I hope to get a url >>>mydomain.com%2FFolder-B%2Fimage1.jpg

Answer

Petah picture Petah · Jun 19, 2012

For PHP < 5.3 use:

$upOne = realpath(dirname(__FILE__) . '/..');

In PHP 5.3 to 5.6 use:

$upOne = realpath(__DIR__ . '/..');

In PHP >= 7.0 use:

$upOne = dirname(__DIR__, 1);

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