How can I maintain the order of actual list after counting its occurrence using a hash in the following program? For example, <DATA>
are
a
b
e
a
c
d
a
c
d
b
etc.
Using hash, i counted the occurrence of each element.
and what i want is:
a 3
b 2
e 1
c 2
d 2
but the following program shows me otherwise.
my (%count, $line, @array_1, @array_2);
while ($line = <DATA>) {
$count{$line}++ if ( $line =~ /\S/ );
}
@array_1 = keys(%count);
@array_2 = values(%count);
for(my $i=0; $i<$#array_1; $i++)
{
print "$array_1[$i]\t $array_2[$i]";
}
Hashes are not ordered, but as usual, CPAN offers a solution: Tie::IxHash
use Tie::IxHash;
my %count;
tie %count, 'Tie::IxHash';
while ($line = <DATA>) {
$count{$line}++ if ( $line =~ /\S/ );
}
while( my( $key, $value)= each %count) {
print "$key\t $value";
}