How do I calculate tables size in Oracle

Question

Being used to (and potentially spoiled by) MSSQL, I'm wondering how I can get at tables size in Oracle 10g. I have googled it so I'm now aware that I may not have as easy an option as sp_spaceused. Still the potential answers I got are most of the time outdated or don't work. Probably because I'm no DBA on the schema I'm working with.

Would anyone have solutions and or recommendations?

Answer 1

You might be interested in this query. It tells you how much space is allocated for each table taking into account the indexes and any LOBs on the table. Often you are interested to know "How much spaces the the Purchase Order table take, including any indexes" rather than just the table itself. You can always delve into the details. Note that this requires access to the DBA_* views.

COLUMN TABLE_NAME FORMAT A32
COLUMN OBJECT_NAME FORMAT A32
COLUMN OWNER FORMAT A10

SELECT
   owner, 
   table_name, 
   TRUNC(sum(bytes)/1024/1024) Meg,
   ROUND( ratio_to_report( sum(bytes) ) over () * 100) Percent
FROM
(SELECT segment_name table_name, owner, bytes
 FROM dba_segments
 WHERE segment_type IN ('TABLE', 'TABLE PARTITION', 'TABLE SUBPARTITION')
 UNION ALL
 SELECT i.table_name, i.owner, s.bytes
 FROM dba_indexes i, dba_segments s
 WHERE s.segment_name = i.index_name
 AND   s.owner = i.owner
 AND   s.segment_type IN ('INDEX', 'INDEX PARTITION', 'INDEX SUBPARTITION')
 UNION ALL
 SELECT l.table_name, l.owner, s.bytes
 FROM dba_lobs l, dba_segments s
 WHERE s.segment_name = l.segment_name
 AND   s.owner = l.owner
 AND   s.segment_type IN ('LOBSEGMENT', 'LOB PARTITION')
 UNION ALL
 SELECT l.table_name, l.owner, s.bytes
 FROM dba_lobs l, dba_segments s
 WHERE s.segment_name = l.index_name
 AND   s.owner = l.owner
 AND   s.segment_type = 'LOBINDEX')
WHERE owner in UPPER('&owner')
GROUP BY table_name, owner
HAVING SUM(bytes)/1024/1024 > 10  /* Ignore really small tables */
ORDER BY SUM(bytes) desc
;