Fragment shader and coloring a texture

Question

I'm trying to make sense of adjusting texture colors with a fragment shader. My fragment shader is super simple:

uniform sampler2D sampler;

void main() {
  vec4 tex = texture2D ( sampler, uvVarying );
  gl_FragColor = vec4(tex.r, tex.g, tex.b, tex.a);
}

This draws my dog texture as expected:

if I then change the shader to

  gl_FragColor = vec4(tex.r, tex.g, tex.b, 1.0);

the result is what I expected, transparency info is lost:

but if I instead set it to:

  gl_FragColor = vec4(tex.r, tex.g, tex.b, 0.0);

I was expecting it to disappear completely, but instead I get:

What is going on??

And to my original problem: I wanted to add a little red tint to my texture with:

  gl_FragColor = vec4(tex.r + 0.5, tex.g, tex.b, tex.a);

Now, I was expecting it to have same transparency info as the original texture, but instead I get this:

What am I missing here. The texture is using default blending of the engine which is src = GL_ONE, dst = GL_ONE_MINUS_SRC_ALPHA.

Answer 1

Your blending mode assumed pre-multiplied alpha, which normally is a great choice. But it requires the RGB values to be multiplied with the alpha value. The alpha value only controls, how much of the background gets added to the incoming fragments in that mode. So to make RGB "fade out" they must be modulated by the alpha value as well.

Now when you're messing with that alpha value to be constant, your RGB values no longer match that premultiplication. Try this instead for your red tinting:

gl_FragColor = tex + vec4(0.5, 0, 0, 1)*tex.a;

This adds a alpha modulated red to the texture.

In the case you expect the image to disappear completely, you'd require a different blending mode, namely GL_SRC_ALPHA, GL_ONE_MINUS_SRC_ALPHA, but with that you require a non-premultiplied-alpha image, or you compensate that premultiplication in the shader:

gl_FragColor = vec4(tex.rgb/tex.a, tex.a);