I have an NSString with the value of
http://digg.com/news/business/24hr
How can I get everything before the 3rd level?
http://digg.com/news/
This isn't exactly the third level, mind you. An URL is split like that way:
http
)://
delimiterusername:password@hostname
)digg.com
):80
after the domain name for instance)/news/business/24hr
)?foo=bar&baz=frob
)#foobar
).A "fully-featured" URL would look like this:
http://foobar:[email protected]:8080/some/path/file.html;params-here?foo=bar#baz
NSURL
has a wide range of accessors. You may check them in the documentation for the NSURL
class, section Accessing the Parts of the URL. For quick reference:
-[NSURL scheme]
= http-[NSURL resourceSpecifier]
= (everything from // to the end of the URL)-[NSURL user]
= foobar-[NSURL password]
= nicate-[NSURL host]
= example.com-[NSURL port]
= 8080-[NSURL path]
= /some/path/file.html-[NSURL pathComponents]
= @["/", "some", "path", "file.html"] (note that the initial / is part of it)-[NSURL lastPathComponent]
= file.html-[NSURL pathExtension]
= html-[NSURL parameterString]
= params-here-[NSURL query]
= foo=bar-[NSURL fragment]
= bazWhat you'll want, though, is something like that:
NSURL* url = [NSURL URLWithString:@"http://digg.com/news/business/24hr"];
NSString* reducedUrl = [NSString stringWithFormat:
@"%@://%@/%@",
url.scheme,
url.host,
url.pathComponents[1]];
For your example URL, what you seem to want is the protocol, the host and the first path component. (The element at index 0 in the array returned by -[NSString pathComponents]
is simply "/", so you'll want the element at index 1. The other slashes are discarded.)