I have an NSArray, and I want to split it into two equal pieces (if odd "count" then add to the latter new array) - I want to split it "down the middle" so to speak.
The following code does exactly what I want, but is there a better way?:
// NOTE: `NSArray testableArray` is an NSArray of objects from a class defined elsewhere;
NSMutableArray *leftArray = [[NSMutableArray alloc] init];
NSMutableArray *rightArray = [[NSMutableArray alloc] init];
for (int i=0; i < [testableArray count]; i=i+1) {
if (i < [testableArray count]/2) {
[leftArray addObject:[testableArray objectAtIndex:i]];
}
else {
[rightArray addObject:[testableArray objectAtIndex:i]];
}
}
Once leftArray and rightArray are made, I will not change them, so they do not need to be "mutable". I think there may be a way to accomplish the above code with the ObjectsAtIndexes method or some fast enumeration method?, but I cannot get the following code to work (or other variations):
NSArray *leftArray = [[NSArray alloc] initWithObjects:[testableArray objectsAtIndexes:[NSIndexSet indexSetWithIndexesInRange:NSMakeRange(????, ????)]]];
NSArray *rightArray = [[NSArray alloc] initWithObjects:[testableArray objectsAtIndexes:[NSIndexSet indexSetWithIndexesInRange:NSMakeRange(????, ????)]]];
Does anyone know if I am going in the right direction with this or point me in the correct direction?
Thanks!
You also have the option of using -subarrayWithRange:
detailed in the NSArray
documentation:
NSArray *firstHalfOfArray;
NSArray *secondHalfOfArray;
NSRange someRange;
someRange.location = 0;
someRange.length = [wholeArray count] / 2;
firstHalfOfArray = [wholeArray subarrayWithRange:someRange];
someRange.location = someRange.length;
someRange.length = [wholeArray count] - someRange.length;
secondHalfOfArray = [wholeArray subarrayWithRange:someRange];
This method returns new, autorelease
-d arrays.