So I'm running tasks in npm package scripts but I want to pass the watch option in npm start
.
This works:
"scripts": {
"scss": "node-sass src/style.scss dist/style.css -w"
}
This doesn't compile, watch, or throw any error:
"scripts": {
"scss": "node-sass src/style.scss dist/style.css",
"start": "parallelshell \"npm run scss -- -w\""
}
Doesn't work without parallelshell either or without shorthand.
I assume the problem is the run-script is passing the extra argument in quotes, so the command comes out like:
node-sass src/style.scss dist/style.css "-w"
I'd like this to work without adding any dependencies. What am I missing?
Btw, I'm in Windows 10 with command prompt/git bash.
This is my setup for css building
"scripts": {
"css": "node-sass src/style.scss -o dist",
"css:watch": "npm run css && node-sass src/style.scss -wo dist"
},
"devDependencies": {
"node-sass": "^3.4.2"
}
The -o flag sets the directory to output the css. I have a non-watching version "css" because the watching version "css:watch" ~doesn't build as soon as it's run~, it only runs on change, so I call
npm run css
before calling
node-sass src/style.scss -wo dist
If you only want it to run on change, and not when first run, just use
"css:watch": "node-sass src/style.scss -wo dist"