How to store routes in separate files when using Hapi?

Question

All of the Hapi examples (and similar in Express) shows routes are defined in the starting file:

var Hapi = require('hapi');

var server = new Hapi.Server();
server.connection({ port: 8000 });

server.route({
  method: 'GET',
  path: '/',
  handler: function (request, reply) {
    reply('Hello, world!');
  }
});

server.route({
  method: 'GET',
  path: '/{name}',
  handler: function (request, reply) {
    reply('Hello, ' + encodeURIComponent(request.params.name) + '!');
  }
});

server.start(function () {
  console.log('Server running at:', server.info.uri);
});

However, it's not hard to image how large this file can grow when implementing production application with a ton of different routes. Therefore I would like to break down routes, group them and store in separate files, like UserRoutes.js, CartRoutes.js and then attach them in the main file (add to server object). How would you suggest to separate that and then add?

Answer 1

You can create a separate file for user routes (config/routes/user.js):

module.exports = [
    { method: 'GET', path: '/users', handler: function () {} },
    { method: 'GET', path: '/users/{id}', handler: function () {} }
];

Similarly with cart. Then create an index file in config/routes (config/routes/index.js):

var cart = require('./cart');
var user = require('./user');

module.exports = [].concat(cart, user);

You can then load this index file in the main file and call server.route():

var routes = require('./config/routes');

...

server.route(routes);

Alternatively, for config/routes/index.js, instead of adding the route files (e.g. cart, user) manually, you can load them dynamically:

const fs = require('fs');

let routes = [];

fs.readdirSync(__dirname)
  .filter(file => file != 'index.js')
  .forEach(file => {
    routes = routes.concat(require(`./${file}`))
  });

module.exports = routes;