How to extract common / significant phrases from a series of text entries

arronsky picture arronsky · Mar 16, 2010 · Viewed 55.9k times · Source

I have a series of text items- raw HTML from a MySQL database. I want to find the most common phrases in these entries (not the single most common phrase, and ideally, not enforcing word-for-word matching).

My example is any review on Yelp.com, that shows 3 snippets from hundreds of reviews of a given restaurant, in the format:

"Try the hamburger" (in 44 reviews)

e.g., the "Review Highlights" section of this page:

http://www.yelp.com/biz/sushi-gen-los-angeles/

I have NLTK installed and I've played around with it a bit, but am honestly overwhelmed by the options. This seems like a rather common problem and I haven't been able to find a straightforward solution by searching here.

Answer

dmcer picture dmcer · Mar 16, 2010

I suspect you don't just want the most common phrases, but rather you want the most interesting collocations. Otherwise, you could end up with an overrepresentation of phrases made up of common words and fewer interesting and informative phrases.

To do this, you'll essentially want to extract n-grams from your data and then find the ones that have the highest point wise mutual information (PMI). That is, you want to find the words that co-occur together much more than you would expect them to by chance.

The NLTK collocations how-to covers how to do this in a about 7 lines of code, e.g.:

import nltk
from nltk.collocations import *
bigram_measures = nltk.collocations.BigramAssocMeasures()
trigram_measures = nltk.collocations.TrigramAssocMeasures()

# change this to read in your data
finder = BigramCollocationFinder.from_words(
    nltk.corpus.genesis.words('english-web.txt'))

# only bigrams that appear 3+ times
finder.apply_freq_filter(3)

# return the 10 n-grams with the highest PMI
finder.nbest(bigram_measures.pmi, 10)