I encounter a JPA/Hibernate mapping problem on a column "language" in a MySQL table whose type is char(7). In my entity, the code generated for the field is:
private String language;
this causes the following exception at runtime:
... 43 more
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: prosvetaPersistenceUnit] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:911)
at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:74)
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:225)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:308)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1477)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1417)
... 58 more
Caused by: org.hibernate.HibernateException: Wrong column type in joo16_dev.jos_categories for column language. Found: char, expected: varchar(255)
at org.hibernate.mapping.Table.validateColumns(Table.java:283)
at org.hibernate.cfg.Configuration.validateSchema(Configuration.java:1313)
at org.hibernate.tool.hbm2ddl.SchemaValidator.validate(SchemaValidator.java:139)
at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:378)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1842)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:902)
... 63 more
Thanks in advance !
JP
Try this:
@Column(name="language",columnDefinition="char(7)")
see if that works.