Integrity constraint violation: 1062 Duplicate entry '1' for key 'PRIMARY'

Evert van de Lustgraaf picture Evert van de Lustgraaf · Oct 14, 2013 · Viewed 100.7k times · Source

I have a databse problem where i get Integrity constraint violation: 1062. I tried some things on my own but it didtn work so now i am asking you guys to see if you people can help me out.

elseif($action == 'add') {
if($_POST['create'] == true) {
    $title = $_POST['txtTitle'];
    $txtParentCategorie = $_POST['txtParentCategorie'];
    $txtContent = $_POST['txtContent'];

    if($txtParentCategorie == "niks") {
        $txtParentCategorie = NULL;
        $chkParent = 1;
        $order_count = countQuery("SELECT categorieID FROM prod_categorie WHERE parentID=?",array(1));
        $order = $order_count + 1;
    } else {
        $chkParent = null;
        $order_count = countQuery("SELECT categorieID FROM prod_categorie WHERE parentID is not NULL");
        $order = $order_count + 1;
    }

    Query("INSERT INTO prod_categorie (categorieID, parentID) VALUES (?, ?)", array($chkParent, $txtParentCategorie));
    $inserted_id = getLastInsertId();
    Query("INSERT INTO tekst (tabel, kolom, item_id, tekst, taalID) VALUES(?, ?, ?, ?, ?)", array('prod_categorie', 'categoriename', $inserted_id, $title, $lang));
    Query("INSERT INTO tekst (tabel, kolom, item_id, tekst, taalID) VALUES(?, ?, ?, ?, ?)", array('prod_categorie', 'content', $inserted_id, $txtContent, $lang));
    $languages = selectQuery("SELECT taalID FROM taal WHERE taalID!=?",array($lang));
}

when i run this the first INSERT INTO doesnt fill in any data and giving this error: Integrity constraint violation: 1062 Duplicate entry '1' for key 'PRIMARY' there already is a primary 1 key in there. but it is on auto increment. in the tekst tabel the item_id gets an 0 input.

Javascript:

    $('.btnAddCategorie').click(function(){
    if(busy != 1){
        busy = 1;
        var error = 0;
        var gallery = $('select[name="gallery_dropdown"]').val();
        if($('input[name="txtTitle"]').val() == ''){
            error = 1;
            alert('Het titel veld is nog leeg');
            $('input[name="txtTitle"]').focus();
        }
        if(error != 1){
            $('.content_load_icon').html('<img src="../../includes/images/layout/load_small.gif" />');
            var content = $('#cke_ckeditor').children().children().children()[3].contentWindow.document.childNodes[1].childNodes[1].innerHTML;
            $.ajax({
                url: '../../action/ac_productbeheer.php?a=add',
                type: 'POST',
                data: {txtTitle: $('input[name="txtTitle"]').val(), txtForm: $('select[name="txtForm"]').val(), customGalTitle: $('.txtCustomGalleryTitle').val(), gallery_dropdown: gallery, txtParentCategorie: $('select[name="txtParentCategorie"]').val(), txtContent: content, txtMeta: $('.txtMetaDesc').val(), create: true},
                success: function(data, textStatus, xhr) {
                    $('.content_load_icon').html('');
                    $('.txtContentConsole').html('Product succesvol opgeslagen!').show().delay(2000).fadeOut(200);
                    busy = 0;
                    saved = 1;
                    window.location = '../../modules/productbeheer/index.php';
                },
                error: function(xhr, textStatus, errorThrown) {
                    $('.content_load_icon').html('');
                    $('.txtContentConsole').html('Fout bij opslaan! Probeer het later nog een keer.').show().delay(2000).fadeOut(200);
                    busy = 0;
                }
            });
        } else {
            error = 0;
            busy = 0;
        }
    }
});

html:

<a  class="btnAddCategorie"><img name="btnOpslaan" src="/'.CMS_ROOT.'/includes/images/layout/opslaan.png" /></a><span  class="content_load_icon"></span><span  class="txtContentConsole"></span>

Hope someone can help me on here. already alot of thanks in advance. :)

Answer

asantaballa picture asantaballa · Oct 14, 2013

When inserting into a table with an auto increment field, the auto increment field itself should not be specified at all.

Query("INSERT INTO prod_categorie (categorieID, parentID) VALUES (?, ?)", array($chkParent, $txtParentCategorie));
                                   ^^^^^^^^^^^                    ^             ^^^^^^^^^^

Should be just

Query("INSERT INTO prod_categorie (parentID) VALUES (?)", array($txtParentCategorie));

Just added as answer from comment discussion to allow accept and finishing the question.