I have a table named datas
and I'm executing a query like this:
SELECT linkurl AS DOWNLOADURL,
lastrevlevel AS VERSION,
code AS DESCRIPTION,
created AS RELEASEDATE,
name AS TYPE
FROM datas
WHERE id IN (SELECT child_id
FROM datas _datas
WHERE parent_id = (SELECT Max(id)
FROM datas
WHERE code = 'AN4307SW'))
It returns results like this:
DOWNLOADURL VERSION DESCRIPTION RELEASEDATE TYPE
/artifacts/download.txt 2.0 images 25/6/12 download.txt
In the Type
column I am geting name of the file. I need to get the file extension of the file name in the Type
column. How can I achieve this?
Examples:
TYPE
.txt
.pdf
.xls
You can use SUBSTRING_INDEX
. Like this:
select linkurl as DOWNLOADURL,lastrevlevel as VERSION,
code as DESCRIPTION,created as RELEASEDATE,
SUBSTRING_INDEX(name,'.',-1) as TYPE
from datas where id in
(select child_id from datas _datas
where parent_id=( select max(id) from datas
where code = 'AN4307SW'))
EDIT
If you see the docs on this function I think this will apply well to you requirements.
Returns the substring from string str before count occurrences of the delimiter delim. If count is positive, everything to the left of the final delimiter (counting from the left) is returned. If count is negative, everything to the right of the final delimiter (counting from the right) is returned. SUBSTRING_INDEX() performs a case-sensitive match when searching for delim.
This will also handle a case like this:
select SUBSTRING_INDEX('Test.Document.doc','.',-1);
EDIT2
If you are using oracle. Please tag the question in the correct matter next time. There is no SUBSTRING_INDEX
in oracle. But what I can see you can do this quite easy:
SELECT SUBSTR('Test.Document.doc', INSTR('Test.Document.doc', '.',-1))
FROM dual;
Full query like this:
select linkurl as DOWNLOADURL,lastrevlevel as VERSION,
code as DESCRIPTION,created as RELEASEDATE,
SUBSTR(name, INSTR(name, '.',-1)) as TYPE
from datas where id in
(select child_id from datas _datas
where parent_id=( select max(id) from datas
where code = 'AN4307SW'))
Reference here