I have been searching for this almost all day. The general form of the log transformation is
s = clog(1+r)
where
c = 0.1
The opposite is inverse log transformation(book). What will be the inverse log transformation? Is it
s = exp(r)
?
Could not get right output.
Exp()
will only be an inverse of Log()
if Log()
is the natural logarithm. If your Log()
is using a different base (base 2, base 10, any other arbitrary base), then you will need to use the different base in place of e
in Exp()
.
Update
Try 10^(x/0.1)-1
. x/0.1
undoes the 0.1 *
operation, 10^
undoes the log()
, and -1
undoes the +1
.