one Dimensional gauss convolution function in Matlab

Hani picture Hani · Dec 2, 2009 · Viewed 10.1k times · Source

I am trying to write a function that returns a one dimentional gauss filter. the function took sigma as a parameter. The problem is that the function returns the same array for all sigmas.

  function gaussFilter=gauss(sigma)  
  width = 3 * sigma;  
  support = (-width :sigma: width);  
  gaussFilter= exp( - (support).^2 / (2*sigma^2));   
  gaussFilter = gaussFilter/ sum(gaussFilter);  

Note that support array is calculated correctly but the problem arise when applying the exp.

Answer

Jacob picture Jacob · Dec 2, 2009

There is nothing wrong with the results. Your support vector is essentially,

[-3*sigma -2*sigma -1*sigma 0 1*sigma 2*sigma 3*sigma]

And if you square each element of support and multiply by -1, -support.^2

[-9*sigma^2 -4*sigma^2 -1*sigma^2 0 -1*sigma^2 -4*sigma^2 -9*sigma^2]

So dividing it by 2*sigma^2 will always result in the same vector,

[-9/2 -4/2 -1/2 0 -1/2 -4/2 -9/2]

Or

-4.5000   -2.0000   -0.5000         0   -0.5000   -2.0000   -4.5000

So that's why you always get the same answer.

So you need to check your algorithm for making a one-dimensional gaussian filter.

EDIT:

Your original code is fine: except I don't understand why you've made support with -3*sigma:sigma:3*sigma - you should change it to support = -3:3.

You can also use:

gaussFilter = fspecial('gaussian',[1 7],sigma)

EDIT: Check out Amro's solution for the full code and explanation why support = -3*sigma:3*sigma and not support = -3*sigma:sigma:3*sigma