Parse ifconfig to get only my IP address using Bash

macos bash awk ifconfig

Fernando Retimo · May 29, 2014 · Viewed 49.4k times · Source

I want to edit the bashrc file to have a simple function called "myip" to run. As you might guess, the function myip prints only my internal IP address of my machine.

The far as I got working, this is the script:

ifconfig en1 | awk '{ print $2}' | sort

Which got my this output:

10.0.0.12
options=1<PERFORMNUD>
flags=8863<UP,BROADCAST,SMART,RUNNING,SIMPLEX,MULTICAST>
fe80::daa2:5eff:fe96:ba2f%en1
d8:a2:5e:96:ba:2f
autoselect
active

I'm working on Mac OS X.

How can I get this done?

Answer

Both the following work here (CentOS 5).

ip addr show eth0 | awk '$1 == "inet" {gsub(/\/.*$/, "", $2); print $2}'

ifconfig eth0 | awk '/inet addr/ {gsub("addr:", "", $2); print $2}'

For OS X (v10.11 (El Capitan) at least):

ifconfig en0 | awk '$1 == "inet" {print $2}'

Parse ifconfig to get only my IP address using Bash

Answer

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